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SW/알고리즘 문제풀이

[Codility] Lesson2 - Arrays: Cyclic Rotation

by 미래미래로 2020. 12. 14.
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app.codility.com/programmers/lessons/2-arrays/cyclic_rotation/

 

CyclicRotation coding task - Learn to Code - Codility

Rotate an array to the right by a given number of steps.

app.codility.com

 

Problem

An array A consisting of N integers is given. Rotation of the array means that each element is shifted right by one index, and the last element of the array is moved to the first place. For example, the rotation of array A = [3, 8, 9, 7, 6] is [6, 3, 8, 9, 7] (elements are shifted right by one index and 6 is moved to the first place).

The goal is to rotate array A K times; that is, each element of A will be shifted to the right K times.

Write a function:

class Solution { public int[] solution(int[] A, int K); }

that, given an array A consisting of N integers and an integer K, returns the array A rotated K times.

For example, given

A = [3, 8, 9, 7, 6] K = 3

the function should return [9, 7, 6, 3, 8]. Three rotations were made:

[3, 8, 9, 7, 6] -> [6, 3, 8, 9, 7] [6, 3, 8, 9, 7] -> [7, 6, 3, 8, 9] [7, 6, 3, 8, 9] -> [9, 7, 6, 3, 8]

For another example, given

A = [0, 0, 0] K = 1

the function should return [0, 0, 0]

Given

A = [1, 2, 3, 4] K = 4

the function should return [1, 2, 3, 4]

Assume that:

  • N and K are integers within the range [0..100];
  • each element of array A is an integer within the range [−1,000..1,000].

In your solution, focus on correctness. The performance of your solution will not be the focus of the assessment.

 

Solution(c++)

// you can use includes, for example:
#include <bits/stdc++.h>

// you can write to stdout for debugging purposes, e.g.
// cout << "this is a debug message" << endl;

vector<int> newVector;
vector<int> solution(vector<int> &A, int K) {
    // write your code in C++14 (g++ 6.2.0)
    int len = A.size();
    int point = 0;
    // cout << len << endl;
    for(int i=0; i<K; i++){
        if(point==0){
            point = len-1;
        }else{
            point -= 1;
        }
    }
    
    // cout << point << endl;
    for(int i=0; i<len; i++){
        newVector.push_back(A[point]);
        if( point == len-1){
            point = 0;
        }else{
            point += 1;
        }
    }

    return newVector;
}

 

Test Result

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